Two fair dice are rolled. what is the probability that the first lands on a 6 and the second lands on an odd number? show your work! use the sample space from question 8 to assist you! write your answer in simplified fraction form.

1/12

Step-by-step explanation:

There are two dices being rolled. A dice has six faces numbered from one to six. A fair dice means that the probability of each number to appear is equal. Thus the probability of any number showing up is:

P(a number appears on the dice) = how much times the number has been displayed on the dice/number of faces of the dice.

Since all numbers appear once, and there are six sides of a dice. therefore:

P(a number appears on the dice) = 1/6. Thus, P(6 appears on a dice) = 1/6.

As far as the odd numbers are concerned, there are three even numbers and three odd numbers on the dice. So P(odd number appears on the dice) = 3/6 = 1/2.

Assuming that the probabilities of both the dices are independent, we can safely multiply both the probabilities. Thus:

P(first dice lands on a 6 and second dice lands on an odd number) = 1/6 * 1/2 = 1/12.

Thus, the final probability is 1/12!!!

y-3=-3/2(x+4)

ur very much welcome

the correct answers are 1, 2, 4, and 5! i just got it right!