What is the square root of  ab2?

sqrt.(a) * absolutevalue(b)

Step-by-step explanation:

You do abs value when you have an even exponent with an odd exponent result from b^2 to b^1.

Please mark for Brainliest

For more questions or more information, please comment below!

Hello there!

Well, the square root is the inverse function of the square potential.

This is if you have and

A interesting part of the square root is that (-4)*(-4) = 16, and 4*4 = 16, so the solutions for are -4 and 4. For this is that you see a +- symbol in the second equation.

Now, if you have the number

Now, we put this inside a square root:

So the solutions for the square root of (a*b)^2 are a*b and - a*b.

x² + 11x + 18 < 0  

[-11 ± sqrt(121 - 72)]/2 = (-11 ± 7)/2  

solution: (-9, -2)

step-by-step explanation:

yes.. it's proven to be 36.