Aparallelogram whose vertices have coordinates r(1, -1), s(6, 1), t(8, 5), and u(3, 3) has a shorter diagonal of . 5 √(13) √(97)

Step-by-step explanation:

The given parallelogram has vertices R(1, -1), S(6, 1), T(8, 5), and U(3, 3) .

Recall the distance formula;

We use the distance formula to determine the length of the diagonals.

For diagonal R(1,-1) and T(8,5), We have;

For the diagonal S(6,1) U(3,3)

Therefore the shorter diagonal is:

i believe the answer is the polygon, heptagon.

x= 3^y

step-by-step explanation: