6. a restaurant offers a lunch special in which a customer can select from one of the 7 appetizers, one of the 10 entrees, and one of the 6 desserts. how many different lunch specials are possible? show your work

The answer is 420 lunch specials

Step-by-step explanation:

10×7=70 70×6=420

the total different lunches is 420

Step-by-step explanation:

Given that:

As we know that, a customer can choose 3 of the above items in their lunch and it is a combination problem.

So we have:

So the total different lunches is:

P(A) *P(E)*P(D)

= 7*10*6

= 420

Hope it will find you well.

the answer is (-4,-4)

hope this ! : d