Johnny deposited $1230 in a savings account at 2.25 percent interest. how much interest will the account earn in 10 years? $212.50 $291.25 $276.75 $202.25 will got an insurance check of $4500 after a car accident. he deposited it into a savings account at 1.7 percent interest for five years. what was the total amount of money in the account after five years? 1. $4462.50 2. $4882.50 3. $4374.38 4. $4315.63

276.75

Step-by-step explanation:

Deposit 1230. paying 2.25 % 10 yrs.

the interest is 276.75 and the amount is 1506.75

The answer to the first question is $276.75     and the answer to the second question is $4882.50

Step-by-step explanation:

Johnny deposited $1230 in a savings account at 2.25 percent interest. How much interest will the account earn in 10 years?

To solve this, we simply use the simple interest formula;

Simple Interest = PRT / 100

where p is the principal, R is the rate and T is the time (in years)

In this question principal = $1230  rate = 2.25   and time = 10

We can now plug the variables into the formula;

Simple Interest = PRT / 100

                           =$1230  × 2.25× 10    /     100

                             = $27675  / 100

                              = $276.75

Therefore, the amount of interest earn in 10 years is  $276.75

Will got an insurance check of $4500 after a car accident. He deposited it into a savings  account at 1.7 percent interest for five years. What was the total amount of money in the  account after five years?

We can also solve this second part of the question using the simple interest formula, here;

principal = $4500

Rate =1.7

Time =5

We will now insert our values into the simple interest formula, thus;

Simple Interest = PRT / 100

                          =$4500 × 1.7 × 5   / 100

                          =$38250 / 100

                          =$382.50

Simple interest =$382.50

Total amount = $4500 + $382.50

                      =$4882.50

Therefore, the total amount in the account after five years is $4882.50

la parábola es el lugar

geométrico en el cual los puntos tienen una distancia idéntica, equidistantes,

de un punto denominado foco, f, y una recta denominada directriz

el radio vector de una

parábola es el segmento que existe entre un punto cualquiera y el foco.

por la ecuación se observa

que la parábola abre hacia la derecha, por lo cual podemos usar las siguientes fórmulas

la ecuación ordinaria de la

parábola es y^2 = 4px, donde p es la longitud desde el vértice de la parábola al

foco.

la fórmula de la directriz

es x + p = 0

resolviendo:

y^2-9x = 0

y^2 = 9x

4p = 9, entonces p = 9/4

entonces el foco tendrá la

coordenada f(9/4,0)

la directriz vendrá

expresada por

x + p = 0

x = -p

x = -9/4

el problema indica que la

ordenada es igual a 6, entonces

(6)^2=9x

x = 36/9

x = 4

entonces el punto al cual

hay que obtener la distancia será p(4,6)

calculando se tendrá: pf = 

pf = 6,25 u

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step-by-step explanation: