Need fast puleasee fast asap what is the probability of drawing three black cards, one at a time with replacement, from a standard deck of 52 cards? a.'3/52its not bc.1/8d.75/676need fastttgive p(6,6) and q=(-5,-3) find the magnitude of 2p+3qa.2 sqr3b. 3 sqr2its not cd.14according to nfl statistics, the cincinnati bengals will lose 13 out of 16 games, regardless of opponent. what are the odds of cincinnati losing a game? a.3; 13its not bc.13; 3d16; 13determine which trigonometric function to use to solve for the hypotenuse. then, solve for the length of the hypotneuse. b=9a=55.8a. cosin, .062b. sin,10.8c. sin,16.0its not d

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Step-by-step explanation:

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.