Solve 6y2-5y-6 = 0 using the quadratic formula. a) y=- 3 over 2 or y =2 over 3b) y = -5 or y = -6c) y or y=-2d) y = 2 or y = 3

Ay=3 over 2 or y=-2 over 3

Step-by-step explanation:

the quadratic formula: y={-b±√(b²-4ac)}/2a

In the equation 6y²-5y-6= 0, a=6, b=-5, c= -6

Substituting for the values in the formula we get:

{-(-5)±√[(-5²)-4(6)(-6)}/2(6)

{5±√169}12

={5±13}/12

(5+13)/12=3/2 or (5-13)/12= -2/3

or

Step-by-step explanation:

We have the expression

For an equation of the form  the quadratic formula is

In this case

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step-by-step explanation:

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