6) use the steps to solve this system of equations. show your work. y=x+2 y=x^2-4

y= x + 2 and  y = x^2 - 4

Substitute mx + b for y

x^2 - 4 = x + 2

Solve for x

x^2 - 4 = x + 2

x^2 - x - 6 = 0

(x - 3)(x + 2) = 0

x - 3 = 0; x = 3

x + 2 = 0; x = -2

Substitute the first x value  into the linear equation and solve for y

y = 3 + 2

y = 5

One solution is (3, 5)

Substitute the second x value into the  linear equation and solve for y

y = -2 + 2

y = 0

Another solution is (-2 , 0)