Need will give brainliest! what is the equation of the line that is parallel to y-3x=2 and that passes through (6,1)? y=3x-17 y=3x+19 y=-3x+19 y=-3x-17

ANSWER

EXPLANATION

The given line has equation;

We solve for y to get;

The slope of this line is 3.

Since tyheline is parallel to this line, it also has slope 3.

The line passes through (6,1), we can use the slope intercept form,

We substitute the point and the slope to get;

First Option

Step-by-step explanation:

For a linear equation of the form

the slope of the line is the constant m.

In this case we have the line

Then the slope is

If the equation of the line sought is parallel to the line then by definition both lines have the same slope m = 3

Therefore the equation of the line sought is:

Where b is a constant that represents the intersection of the line with the y axis.

Where is a point belonging to the line sought.

In this case the point is (6, 1)

So

Finally the equation is:

answer: i'm great at algebra

~coco

step-by-step explanation:

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it