Many newspapers carry a certain puzzle in which the reader must unscramble letters to form words. how many ways can the letters of whyrot be arranged? identify the correct unscrambling, then determine the probability of getting that result by randomly selecting one arrangement of the given letters.

Step-by-step explanation:

There are six unique letters.  Any of the six could be the first letter.  Once we've picked a first letter, that leaves 5 letters that could go second.  So on and so forth.  So the number of ways they can be arranged is:

6×5×4×3×2×1 = 720

The correct unscrambling is "worthy".  So the probability of randomly selecting this order from the 720 possible combinations is 1/720.

0.16 or 16%

step-by-step explanation:

lets take a coin for example.

if you toss it twice, it has a 1/4 chance of landing on heads both times because 1/2 * 1/2 is 1/4.

with the cards, the chance of picking dog is 0.4. having two people pick one is like picking a card twice in a row. so 0.4 * 0.4 is 0.16, or 16%