The letters that form the word algebra are placed in a bowl. what is the probability, as a percent, of choosing a letter other than a and then choosing an a?

Nearly 23.8%

Step-by-step explanation:

The word ALGEBRA consists of letters A, L, G, E, B, R and A (2 letters A and 5 letters other than A).

The probability that the first letter chosen will be other than A is

Then 2 letters A and 4 letters other than A left (6 letters in total). The probabilty that the second letter chosen is A is

Hence, the probability of choosing a letter other than A and then choosing an A is

the answer is 15% decrease

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.