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Mathematics, 24.06.2019 15:30 paulesparsa6
Trapezoid abcd is reflected over the line y = x. what rule shows the input and output of the reflection, and what is the new coordinate of a'? trapezoid abcd is shown. a is at negative 5, 1. b is at negative 4, 3. c is at negative 2, 3. d is at negative 1, 1. (x, y) ? (y, ? x); a' is at (1, 5) (x, y) ? (y, x); a' is at (1, ? 5) (x, y) ? (? x, y); a' is at (5, 1) (x, y) ? (? x, ? y); a' is at (5, ? 1)
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Prove (a) cosh2(x) − sinh2(x) = 1 and (b) 1 − tanh 2(x) = sech 2(x). solution (a) cosh2(x) − sinh2(x) = ex + e−x 2 2 − 2 = e2x + 2 + e−2x 4 − = 4 = . (b) we start with the identity proved in part (a): cosh2(x) − sinh2(x) = 1. if we divide both sides by cosh2(x), we get 1 − sinh2(x) cosh2(x) = 1 or 1 − tanh 2(x) = .
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Trapezoid abcd is reflected over the line y = x. what rule shows the input and output of the reflect...
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