Can someone me factor 6x^2 - 9x+42

3(2x^2-3x+14)

Step-by-step explanation:

6x^2-9x+42

All three terms have a common factor of 3

3(2x^2-3x+14)

Now let's focus on 2x^2-3x+14 and bring down the factor 3 later

so a=2

b=-3

c=14

Let's try to find two factors for ac that multiply to be a*c and add up to be b.

ac=28

b=-3

ac=7(4)=14(2)=8(2)

Even if I made these pairs with both negatives nothing would give me -3

So you can only go as far as 3(2x^2-3x+14)

Here is another thing to help you if you have ax^2+bx+c and b^2-4ac<0 then it can't be factored (over reals)

-3(x-2)(2x+7)

Step-by-step explanation:

it would be a on edgenuit y

the diagram below is your final answer

add 8+12 to get a simplified answer of 12r-20