What are the zeros of the quadratic function f(x) = 6x2 + 12x – 7?

-6 ± √78\6 [0.47196014..., -2.47196014... = x]

Step-by-step explanation:

The roots [zeros] are the x-values where the graph intersects the x-axis. To find the roots (zeros), replace y with 0 and solve for x.

x = 1 + √74/6 or x = 1 - √74/6

Step-by-step explanation:

Points to remember

Zeros of a quadratic equation ax² + bx + c = 0

x = [-b ± √(b² - 4ac)]/2a

To find the zeros of given quadratic equation

It is given that,

6x² +12x - 7 = 0

Here a = 6, b = -12 and c = -7

x = [-b ± √(b² - 4ac)]/2a

 =  [-12 ± √(12² - 4*6*(-7))]/2*6

 = [12 ± √(144 +168 )]/12

 =  [12 ± √312]/12

 = [12 ± 2√74]/12

 = 1 ± √74/6

x = 1 + √74/6 and x = 1 - √74/6