Ahot-air balloon advertising for a real estate company is 250 m above ground level. the angle of depression from the balloon is to the landing area is 30 degrees. what is the distance along the ground from a point beneath the balloon to the landing area?

The answer i'm pretty sure is 14.832

Step-by-step explanation:

In the process A squared + B squared = C squared the variable 250m is C squared and the angle 30 degrees is A or B squared so if you subtract 30 from 250 you get 220 and by taking the square root of that you get the answer 14.832

3/5

step-by-step explanation:

double number line is not a standard concept, so it must have been defined in your textbook. assume top line is numerator.

sas (side angle side)

aa (angle angle)

sss(side side side)

sas find two sides with an angle in between

aa is finding two angles and the third will add up to 180

sss find all sides

step-by-step explanation: