In a survey in 2010, the population of two plant species were found to be growing exponentially. their growth is given by these equations: species a, and species b, , where t = 0 in the year 2010. 4. after how many years will the population of species a be equal to the population of species b in the forest?

If we want to find when the population of species A will be equal to the population of species B, we need to see when the two equations for the population of each species are equal, ie. equate them and solve for t. Thus:

2000e^(0.05t) = 5000e^(0.02t)

(2/5)e^(0.05t) = e^(0.02t) (Divide each side by 5000)

2/5 = e^(0.02t) / e^(0.05t) (Divide each side by e^(0.05t))

2/5 = e^(-0.03t) (use: e^a / e^b = e^(a - b))

ln(2/5) = -0.03t (use: if b = a^c, then loga(b) = c )

t = ln(2/5) / -0.03 (Divide each side by -0.03)

= 30.54 (to two decimal places)

Therefor, the population of species A will be equal to the population of species B after 30.54 years.

I wasn't entirely sure about the rounding requirements so I've left it rounded to two decimal places.

180 square centimeters

step-by-step explanation:

distance covered by pamela in 9 l of fuel = 99km

let us apply unitary method here.

distance covered by pamela in 1 l of fuel =99/9 =11 km

now let us find distance covered by pamela if she has 12 l of fuel.

distance covered in 12 l = distance covered in 1 l of fuel * 12

we know that distance covered by here in 1 l is 11 km.

so distance covered in 12 l of fuel = 11*12 = 132 km.