Suppose that there are two types of tickets to a show: advance and same-day. advance tickets cost $25 and same-day tickets cost $35. for one performance, there were 45 tickets sold in all, and the total amount paid for them was $1375 . how many tickets of each type were sold?

For this case we propose a system of equations:

x: Variable representing the anticipated tickets

y: Variable representing the same day tickets

So:

We clear x from the first equation:

We substitute in the second equation:

We look for the value of x:

Thus, 20 of anticipated type and 25 of same day type were sold.

20 of anticipated type and 25 of same day type were sold.

20 advance tickets and 25 same-day tickets.

Step-by-step explanation:

Set up a system of equations.

Let be "a" the number of advance tickets and "s" the number of same-day tickets.

Then:

You can use the Elimination method. Multiply the second equation by -25, then add both equations and solve for "s":

Substitute into an original equation and solve for "a":

step-by-step explanation:

you can add the two numbers and divide the result by 2. or you can find the gap between the two numbers and add half of this to the smaller number.

where are the images of the functions i can only see the question you typed.

step-by-step explanation: