Atoy rocket is launched straight up into the air with an initial velocity of 60 ft/s from a table 3 ft above the ground. if acceleration due to gravity is –16 ft/s2, approximately how many seconds after the launch will the toy rocket reach the ground? h(t) = at2 + vt + h0

it will take appr 3.8 seconds to hit the ground

Step-by-step explanation:

h = -16t^2 + 60t + 3

at ground level , h = 0

16t^2 - 60t - 3 = 0

t = (60 ± √3792)/32

t = 3.799.. or t = a negative

75 tickets have been sold so far.

step-by-step explanation:

in this question it is clearly mentioned that 45 children's tickets have been sold and this number is 60% of the total tickets sold.

now let's assume the total number of tickets sold be x.

then 60% of x = 45

⇒

⇒ x(.6) = 45

by dividing with .6 on both the sides of the equation

⇒ x = 75

therefore 75 tickets have been sold so far.