Intera population of fish stats at 8,000 and decreases by 6% per year. what would the population of fish be after 10 years? use 4 -

4309

Step-by-step explanation:

initial 8000

1st year 8000(1-.06)=8000(.94)

2nd year 8000(.94)^2

...

10 year 8000(.94)^10 approx 4309

step-by-step explanation:

i found the koficent of the linear function and i foun c acordind to the strict formula y=kx+c and then i took 2 as an x and replacet it on the formula i found and then foun the y

10 down (bang1)

5 up

5down (2)

2.5 up

2.5 down (3)

1.25 up

1.25 down (4)

now add them up : )

hoped i lol