Find y. round to the nearest tenth. !

y ≈ 358.3 ft

Step-by-step explanation:

The angle in the right side of the triangle = 28° ( alternate angle )

Using the tangent ratio in the right triangle to solve for y

tan28° = =

Multiply both sides by y

y × tan28° = 350 ( divide both sides by tan28° )

y = ≈ 658.3 ft

y = 658.3ft. The value of the side y of the right triangle shown in the image is 658.3ft.

The key to solve this problem we have to use the trigonometric functions tan θ = opposite leg/adjacent leg

To find side y, where opposite leg = 350ft, adjacent leg = y, and θ = 28° by symmetry:

tan θ = opposite leg/adjacent leg

tan 28° = 350ft/y

Clear y:

y = 350ft/tan 28°

y = 658.254ft

Round to the nearest tenths y = 658.3ft

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)

i suppose it should be (y=2x-5)

step-by-step explanation: