Arocket lifted off from a launch pad and traveled vertically 30 km, then traveled 40 km at 30 degrees from the vertical, and then traveled 100 km at 45 degrees from the vertical. at that point, the rocket was how many kilometers above the height of the launch pad?

Well, we are told that in the beginning, it has traveled 30km vertically, so do not forget to add that on at the end.

Next it says that it traveled 40km 30 degrees from vertical, so we set up a sin equation to solve for the missing side, n:

sin(angle)= opposite/hypotenuse:

sin(30) = n/40

40sin30=n

n=20km

Then it says at an angle of 45 degrees, it goes 100km. This means that we are given the hypotenuse of a right triangle, and we need to find the side that goes up and down. We shall call this length x.

We know that the angle opposite x is 45 degrees.

So, we will use sin to solve for x:

sin(angle)= opposite/hypotenuse

sin45= x/100

100sin45=x

x=70.711km

But remember, I said not to forget about that 30km from the very beginning? So we add up all of our vertical heights:

30km + 20km+ 70.711km = 120.711km

We need the pictures of the graphs