Acamera manufacturer spends $1,800 each day for overhead expenses plus $9 per camera for labor and materials. the cameras sell for $18 each. a. how many cameras must the company sell in one day to equal its daily costs? b. if the manufacturer can increase production by 50 cameras per day, what would their daily profit be?

Amount of money spent per day = $1800

Cost of overhead expenses per day for labor and materials = $9

Selling price of each camera = $18

a. Let us assume the number of cameras manufactured per day = x dollars

Then

Cost of cameras sold in 1 day = 18x

So

18x = 1800 + 9x

18x - 9x = 1800

9x = 1800

x = 200

From the above deduction, we can conclude that the number cameras sold per day is 200

b. Daily selling amount of 250 cameras = 250 * 18

                                                              = 4500 dollars

Daily manufacturing price of 250 cameras = 1800 + (9 * 250)

                                                                   = 4050 dollars

Then

Daily profit = 4500 - 4050

                 = 450 dollars

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.

i cant answer this, theres no table. sorry man

step-by-step explanation: