Need answer asap! 50 pts! which of the following would best represent a sine function with an amplitude of 7, a period of pi over 4 , and a midline at y = 3? (1 point) f(x) = 7 sin 8x + 3 f(x) = 3 sin 8x + 7 f(x) = 7 sin( pi over 4 x) + 3 f(x) = 3 sin( pi over 4 x) + 7

f(x) = 7 sin 8x + 3 ⇒ 1st answer

Step-by-step explanation:

* Lets revise the trigonometry translation  

- If the equation is y = A sin (B x + C) + D  

* A is the amplitude  

- The amplitude is the height from highest to lowest points and  

  divide the answer by 2  

* The period is 2π/B  

- The period is the distance from one peak to the next peak

* C is the horizontal shift  

- The horizontal shift is how far the function is shifted to left  

  (C is positive) or to right (C is negative) from the original position.  

* D is the vertical shift  

- The vertical shift is how far the function is shifted vertically up

  (D is positive) or down (D is negative) from the original position.  

- The equation of the mid-line is y = D

* Now lets solve the problem

∵ f(x) = A sin(Bx + C) + D

∵ The amplitude is 7

∴ A = 7

∵ The period is 2π/B

∵ The period is π/4

∴ 2π/B = π/4 ⇒ divide both sides by π

∴ 2/B = 1/4 ⇒ Use cross multiplication

∴ B × 1 = 2 × 4

∴ B = 8

∵ The equation of the mid-line is y = D

∵ The equation of the mid-line is y = 3

∴ D = 3

- There is no mention for C

∴ C = 0

∴ f(x) = 7 sin 8x + 3

not enough information

step-by-step explanation:

we cannot know this, because the other students could have handed out 10 flyers, or they could have handed out 100. one way, the mean would go up, and another way, the mean would go down.