1.        at a fundraiser dinner, the bill for 4 cups of coffee and 6 spaghetti specials is $20.50, whereas the bill for 1 cup of coffee and 3 spaghetti specials is $8.75. write a system of 2 equations to model this problem. let c stand for the price of a cup of coffee and let s stand for the price of a spaghetti special. use the substitution method to solve the system of equations. what would the bill be for 1 cup of coffee and 1 spaghetti special? (pls ! )

1- Writing the system of equations:

The price of a cup of coffee is denoted by c while the price of a spaghetti is denoted by s

We are given that:

4 cups of coffee and 6 spaghetti cost $20.5

This means that:

4c + 6s = 20.5 > equation 1

We are also given that:

1 cup of coffee and 3 spaghetti cost $8.75

This means that:

c + 3s = 8.75 > equation 2

2- Solving the equations using substitution methods:

From equation 2:

c = 8.75 - 3s > I

Substitute with I in equation 1 and solve for s as follows:

4c + 6s = 20.5

4(8.75 - 3s) + 6s = 20.5

35 - 12s + 6s = 20.5

35 - 6s = 20.5

6s = 14.5

s = $2.41667

Substitute with s in I to get c:

c = 8.75 - 3s

c = 8.75 - 3(2.41667) = 1.4999 = $1.5

3- getting price for 1 cup of coffee and 1 spaghetti:

c + s = 1.5 + 2.41667 = $3.91667

Hope this helps :)

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