Solve the system. 0.2x + 0.5y = 4 -0.1x + 0.3y = -2 a) (20, 0) b) (-2, 5) c) (-5, 10) d) (50, 10)

  A)  (20, 0)

Step-by-step explanation:

Double the second equation and add that to the first:

  (0.2x +0.5y) +2(-0.1x +0.3y) = (4) +2(-2)

  1.1y = 0

   y = 0

Substitute this value into either equation to find x.

  0.2x +0.5·0 = 4

  x = 4/0.2 = 20

The solution is (x, y) = (20, 0).

i think the answer is seven, for if i'm being useless °ω°

step-by-step explanation:

2x^2+5x+17

your welcome. : )