Compete the square to determine minum or maxuim value of function define by -x2+10x+5

maximum value y = 30

Step-by-step explanation:

Given

- x² + 10x + 5

To complete the square the coefficient of the x² term must be 1

factor out - 1

= - (x² - 10x) + 5

To complete the square

add/subtract ( half the coefficient of the x- term )² to x² - 10x

= - (x² + 2(- 5)x + 25 - 25) + 5

= - (x - 5)² + 25 + 5

= - (x - 5)² + 30 ← in vertex form

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Hence vertex = (5, 30)

The max/ min occurs at the vertex

Since a < 0 then vertex is a maximum

Hence maximum value is y = 30

answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° =

but bc = 20 feet.

⇒ tan 55 ° =  

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet