With this question, i don't understand!

(0, 1)

Step-by-step explanation:

all of the points are the same number away: 2√5

  (0, 1)

Step-by-step explanation:

A, B, and C are points on a circle. You are being asked to find the center of the circle. You can do that any of several ways.

I find it useful to plot the points on a graph. Doing so reveals that AB is perpendicular to BC, so ABC is a right triangle, and the center you want is the midpoint of the hypotenuse (AC).

  (A+C)/2 = ((2, -3) +(-2, 5))/2 = (2-2, -3+5)/2 = (0, 1) . . . . . coordinates of center

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From a construction point of view, the center of the circle is the point of intersection of the perpendicular bisectors of the chords. In the attached, we have used a geometry program to draw the perpendicular bisectors of AB and BC. They meet at (0, 1).

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From an algebra point of view, the points on the circle with center (h, k) and radius r satisfy the equation ...

  (x -h)^2 +(y -k)^2 = r^2

Filling in the point values, you get three equations in the three unknowns (h, k, r):

Finding the difference between any two pairs of these will result in two linear equations in h and k, so are easily solved.

  First - second: (4 -4h +h^2) +(9 +6k +k^2) -(16 -8h +h^2) -(9 -6k +k^2) = r^2 -r^2

  -12 +4h +12k = 0 . . . simplify

  h +3k = 3 . . . . . . . . . put in standard form

  Second -third: (16 -8h +h^2) +(9 -6k +k^2) -(4 +4h +h^2) -(25 -10k +k^2) = r^2 -r^2

  -4 -12h +4k = 0 . . . . simplify

  3h -k = -1 . . . . . . . . . put in standard form

Now, we can add 3 times the second of these equations to the first to find h:

  (h +3k) +3(3h -k) = (3) +3(-1)

  10h = 0

  h = 0

Then either of the equations can be used to find k = 1.

The center is (h, k) = (0, 1).

2 x^2 -3x+p

sum of roots = 3/2

let other root be x

3+ x = 3/2

x= 3/2 - 3 = -3/2

product of roots = p/2

3× -3/2 = p/2

-9 = p

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its kind of blurry. can you put a clearer pic?

step-by-step explanation: