Solve 2/3x > 8 or 2/3x < 4. {x | x > 12 or x < 6} {x | x > 16/3 or x < 8/3} ø

The first choice is the one you want

Step-by-step explanation:

Solve the inequalities one at a time:

Multiply both sides by 3:

2x > 24 and

x > 12

For the next one:

Again, multiply both sides by 3:

2x < 12 and

x < 6

So the solution set is {x I x > 12 or x < 6}

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation:

the answer is c. 23/3