The zero of f -1(x) in f(x) = x + 3 is

We have

y = F(x) = x + 3

so

x = y  - 3

so

F⁻¹(y) = y - 3

which we can write

F⁻¹(x) = x - 3

We solve

0 = F⁻¹(x) = x - 3

x = 3

3

answer:

given the linear inequality :

add 2y to both sides we get;

simplify:

add 12 to both sides of an equation;

simplify:

divide both sides by 2 we get;

or

the related equation for the inequality equation [1] is;

y-intercepts defined as the graph crosses the y-axis.

substitute x =0 in [2] to solve for y;

y = 6

x-intercepts defined as the graph crosses the x-axis.

substitute value y = 0 to solve for x;

subtract 6 from both sides we get

multiply both sides by 2 we get;

or

x = -12

now, plot these point (0, 6) and (-12, 0) on graph as shown below and shade the graph below the solid line.