Which is an equation of the circle with a radius of 9 units and center at (–4, 2)? a. (x − 9)2 + (y + 4)2 = 4 b. (x − 4)2 + (y + 2)2 = 81 c. (x + 4)2 + (y − 2)2 = 81 d. (x − 2)2 + (y + 4)2 = 81

We want (x - h)^2 + (y - k)^2 = r^2.

This circle is not centered at the origin.

The point we want is in the form

(h, k).

We are given that h = -4 and k = 2.

We also know that the radius is 9.

Let r = 9 leading to (9)^2 or 81.

We know substitute in the form given above for circles not centered at the origin.

(x - (-4)^2 + (y - 2)^2 = 81

(x + 4)^2 + (y - 2)^2 = 81

Choice C

step-by-step explanation:

a cube has 6 sides

the probability of getting 5 on the first cube is 1/6 since only one side of the cube has 5 on it.

there are 3 sides of the cube with even number on it [2,4,6]

therefore the probability of getting even number is 3/6

for both events to happen together, the probability would be

1/6 x 3/6 = 12/36

which simplifies to 1/12