11. find three consecutive odd integers such that their sum decreased bythe second equals 50.

The numbers you are looking for are 23, 25, and 27. Let's start by defining a variable.  Let x be the first of the three odd numbers.  Since odd numbers are 2 apart, that means that the other two numbers are x + 2 and x + 4.

Now, their sum is x + (x + 2) + (x + 4) which equals 3x + 6.

Decrease that by the second number, x + 2.  That means:  3x + 6 - (x + 2), which is equal to 2x + 4.

So now we know that 2x + 4 = 50, and we can solve that easily:

2x + 4 = 50

2x = 46

x = 23

Therefore, the three odd numbers are 23, 25, and 27. Hope this helps! Please mark Brainliest. Thank you v much! :)

you can first factor out the n to get n(1+5). we know that 1+5 is 6, so we just have 6n.

"a" determine whether sage found the correct quotient. show your work

step-by-step explanation: