Jeremys father is 11 less than jermeys age squared. if jeremy’s father is 53, how many years older is jeremy’s father than jeremy?

45 years

Step-by-step explanation:

First, lets break the problem down, step-by-step.

Jeremy's age can be represented using the varibale, j.

His father's age is 53, or 11 less than j squared.

Jeremy's father's age can be represented using the following equation:

j^2 - 11 = 53

Now, solve for j.

j^2 - 11 = 53

j^2 = 64

j = 8

That means Jeremy is 8 years old. Now, find the difference between his age and his father's age.

53 - 8 = 45.

So, Jeremy's father is 45 years older than his son.

I hope this helps! :)

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.

linear pair postulates