Assignment: lines of best fit investigation data is shown from a random selection of bamboo plants on a bamboo farm. the number of days since the plant appeared above the soil and the height of the plant are shown. days since bamboo plant appeared above soil height of bamboo plant in centimeters days since bamboo plant appeared above soil height of bamboo plant in centimeters 2 6.5 10 35.2 12 39.9 8 26.4 5 18.5 17 59.4 7 26.6 26 91.3 23 83.1 28 95.0 15 52.4 13 45.4 32 110.1 10 35.8 18 65.0 15 52.7 part a create a clearly labeled scatter plot that shows the relationship between the number of days since the plant appeared above the soil and the height of the plant. draw a trend line on the scatter plot to represent the data. part b 1. which of the following lines of best fit represent the data if x is the number of days since the plant appeared and y is the height of the plant? y = 3.5x + 0.7 2. explain why your choice of equations best fits the data. explain what the slope and y-intercept of the line of best fit mean about the bamboo plants. part c use the line of best fit chosen in part b to predict the height of a bamboo plant 40 days after appearing above the soil. show your work. y= 3.5 (40) + 0.7 y= 140 + 0.7 y= 140.7

it depends on the weather. because i have flown to seattle when it was pouring down rain and there was one time i flew to ohio when it was snowing hard. whats your situation.

step-by-step explanation:

answer: are you

step-by-step explanation:

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.