Which complex number has a distance of the root of 17 from the origin on the complex plane? 2 + 15i 17 + i 20 – 3i 4 – i

  4 -i

Step-by-step explanation:

For your condition to be met, neither the real part nor the imaginary part can exceed √17 in magnitude. That excludes the first three answer choices.

The magnitude of 4-i is ...

  √(4^2 +(-1)^2) = √17.

Step-by-step explanation:

First, we need to know that a complex number, which has a real part and an imaginary part, it's like a vector, where the horizontal coordinate is the real part, and the vertical coordinate is the imaginary part.

So, to find the distances we applied the conventional definition:

Where refers to the real part and refers to the imaginary part.

So, we test each answer and see which one gives us the root of 17.

Therefore, the right answer is the last one, because the distance is the squared root of 17.

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below:

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: