The trajectory of a potato launched from a potato cannon on the ground at an angle of 45 degrees with a speed of 65 meters per second can be modeled by the parabola: y=x-0.0023x^2, where the x-axis is the ground. find the height point of the trajectory and the horizontal distance the potato travels before hitting the ground.

Step-by-step explanation:

The highest point of a parabola is at the vertex.

x = -b / (2a)

x = -1 / (2×-0.0023)

x ≈ 217.4

y = (217.4) − 0.0023 (217.4)²

y ≈ 108.7

The horizontal distance can be found when the potato lands (y=0):

0 = x − 0.0023x²

0 = x (1 − 0.0023x)

x = 0, x ≈ 434.8

So the potato reaches a maximum height of 108.7 m and travels a horizontal distance of 434.8 m.

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.