15 ! the triangle abc is dilated with respect to the point o(8,-3) and the scale factor 3 to a new triangle a'b'c'. what are the coordinates of b? (24,-9) (24,-3) (12,-9) (-4,-3)

(-4,-3)

Step-by-step explanation:

we know that

The distance OB is equal to

(8-4)=4 units

To find the new distance OB', multiply the distance OB by the scale factor

so

OB'=OB*3

OB'=4*3=12 units

The x-coordinate of point B' is equal to

8-12=-4

The y-coordinate of point B' is the same that B  -3

the coordinates of point B'are (-4,-3)

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)

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