What are the domain and range of f(x) =(1/6)^x + 2? a. domain: {x | x > - 1/6} ; range: {y | y > 0} b. domain: {x | x > 1/6} ; range: {y | y > 2} c. domain: {x | x is a real number}; range: {y | y > 2} d. domain: {x | x is a real number}; range: {y | y > –2}

Step-by-step explanation:

Option C

domain: {x | x is a real number}; range: {y | y > 2}

Step-by-step explanation:

We have the function

Note that f(x) is an exponential function.

By definition the exponential functions of the form  have as domain all real numbers and as range {y | y > k}  if ,

Where a is the main coefficient, b is the base and k is the vertical displacement.

In this case , ,

Therefore the domain of f(x) is all real numbers and the range of f(x) is

{y | y > 2}

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step-by-step explanation:

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