Which pair of monomials has the least common multiple (lcm) of 54x2y3? a) 2xy, 27xy2 b) 3x2y3, 18x2y3 c) 6x2, 9y3 d) 18x2y, 27xy3

ANSWER

The correct answer is D.

EXPLANATION

If we express the monomial,

as product of primes, we obtain:

If we express the monomial

as product of primes we obtain:

The least common multiple of these two binomials is the product of the highest powers of the common factors.

The LCM is

Therefore the correct answer is D.

The correct answer is option D.

18x2y, 27xy3

Step-by-step explanation:

To find the LCM

A).To find the Lcm of  (2xy, 27xy2)

LCM((2xy, 27xy2)  = 54xy^2

B).To find the  Lcm of  (3x2y3, 18x2y3)

LCM(3x2y3, 18x2y3)  = 18x^2y^4

C). To find the  Lcm of (6x2, 9y3)

LCM(6x2, 9y3)  = 18y^2y^

D). To find the  Lcm of (18x2y, 27xy3)

 LCM(18x2y, 27xy3) = 54x^2y^3

Therefore the correct answer is option D

18x2y, 27xy3

the data of the detroit pistons in numerical order from least to greatest is 0.30, 0.37, 0.55, 0.62, 0.69, 0.72, 0.73, 0.75, 0.77, 0.78, 0.80, 0.81, 0.81, 0.83, 0.84, 0.89

the data of the miami heat in numerical order from least to greatest is 0.50, 0.50, 0.56, 0.57, 0.67, 0.72, 0.72, 0.72, 0.75, 0.75, 0.76, 0.81, 0.82, 0.90, 1.00, 1.00

the detroit pistons median : 1.52

the miami heat median: 1.47

the iqr of this data is 0.05

4 candies

step-by-step explanation:

7 x 28 = 196

200 - 196 = 4 candies remaining.