In right △abc, the altitude ch to the hypotenuse ab intersects angle bisector al in point d. find the sides of △abc if ad = 8 cm and dh = 4 cm.

Step-by-step explanation:

Consider right triangle ADH ( it is right triangle, because CH is the altitude). In this triangle, the hypotenuse AD = 8 cm and the leg DH = 4 cm. If the leg is half of the hypotenuse, then the opposite to this leg angle is equal to 30°.

By the Pythagorean theorem,

AL is angle A bisector, then angle A is 60°. Use the angle's bisector property:

Consider right triangle CAH.By the Pythagorean theorem,

The length cannot be negative, so CD=8 cm and

In right triangle ABC, angle B = 90° - 60° = 30°, leg AC is opposite to 30°, and the hypotenuse AB is twice the leg AC. Hence,

By the Pythagorean theorem,

10a^3+277a^2-132a-792

step-by-step explanation:

(2a+11)(5a-12)(foil)

=10a^2-24a+55a-132 =10a^2+31a-132

(10a^2+31a-132)(a+6)

=10a^3+60a^2+31a^2+186a^2-132a-792 =10a^3+277a^2-132a-792

i hope this is what you are looking for : )