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the number of chips of different colors in amy's bag is shown below:

8 blue chips

9 pink chips

1 white chip

amy takes out a chip from the bag randomly without looking. she replaces the chip and then takes out another chip from the bag. what is the probability that amy takes out a pink chip in both draws?

9 over 18 multiplied by 8 over 17 equals 72 over 306

9 over 18 plus 8 over 17 equals 297 over 306

9 over 18 multiplied by 9 over 18 equals 81 over 324

9 over 18 plus 9 over 18 equals 18 over 18

(9/18)(9/18) = 81/324. The probability that Amy takes out pink chips in both draws is 81/324.

In this example we will use the probability property P(A∩B), which means given two independent events A and B, their joint probability P(A∩B) can be expressed as the product of the individual probabilities P(A∩B) = P(A)P(B).

The total number of chips of different colors in Amy's bag is:

8 blue chips + 9 pink chips + 1 white chip = 18 color chips

Amy takes out a chip from the bag randomly without looking, she replaces the chip and then takes out another chip from the bag.

So, the probability that Amy takes out a pink chip in the first draw is:

P(A) = 9/18 The probability of takes out a pink chip is 9/18 because there are 9 pink chips in the total of 18 color chips.

Then, Amy replaces the chip an takes out another which means there are again 18 color chips divide into 8 blue chips, 9 pink chips, and 1 white chip. So, the probability of takes out a pink chip in the second draw is:

P(B) = 9/18  The probability of takes out a pink chip is 9/18 because there are 9 pink chips in the total of 18 color chips.

What is the probability that Amy takes out a pink chip in both draws?

P(A∩B) = P(A)P(B)

P(A∩B) = (9/18)(9/18) = 81/324

x

step-by-step explanation: