The height h of a skydiver t seconds after jumping. let t be the independent variable, and assume the skydiver jumps from a height of 12,500 feet and lands after 300 seconds of flight

25 seconds

Step-by-step explanation:

Skydiving.  

height (in feet) above the earth=h(t)= -16t^2 + 10,000

the time it would take to fall when h is 0  

-16t^2 + 10,000=0

-16t^2=-10000

16t^2=10000

t^2=10000/16=625

t=sqrt 625=25 seconds

b

step-by-step explanation:

the equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, 4) and (x₂, y₂ ) = (3, - 5) ← 2 points on the line

m = = = - 3

with m = - 3 and (a, b) = (3, - 5), then

y - (- 5) = - 3(x - 3), that is

y + 5 = - 3(x - 3) → b