What is the value of the interquartile range of the data below? 6 12 14 24

14

Step-by-step explanation:

The interquartile range is the value of quartile 3 minus quartile 1.

The "box" part of this diagram has 3 lines, the left most, the middle, and the rightmost.

The leftmost line is Quartile 1. The right most is Quartile 3.

Hence

interquartile range = quartile 3 - quartile 1

Looking at the box plot, we can see that each small line in the number line is 2 units.

The leftmost line (quartile 1 ) is at 1 unit left of 30, so that is 30 -2 = 28

The rightmost line (quartile 3) is at  1 unit right of 40, so that is 40 + 2 = 42

Hence,

Interquartile range = 42 - 28 = 14

c: 14

Step-by-step explanation:

I see everyone saying it is B or D, but ITS C! The graph is counting by 2, so there fore it is 42-28= 14. :)

more detail

step-by-step explanation:

a.   we have two

lines:   y = 4-x   and  

y = 8-x^-1

given two simultaneous equations that are both to be

true, then the solution is the points where the lines cross. the intersection is

where the two equations are equal. therefore the solution that works for both

equations is when

4-x = 8-x^-1

this is where the two lines will cross and that is the

common point that satisfies both equations.

b.   4-x = 8-x^-1

  x           4-x       8-x^-1

-3           7        

8.33

-2           6         8.5

-1           5         9

  0           4        

-

  1           3        

7

  2           2        

7.5

  3           1         7.67

the table shows that none of the x values from -3 to 3 is

the solution because in no case does

4-x = 8-x^-1

to find the solution we need to rearrange the equation to

find for x:

4-x = 8-x^-1

multiply both sides with x:

4x-x^2 = 8x-1

x^2+4x-1=0

x= -4.236, 0.236

therefore there are two points that satisfies the

equation.

find y:  

x=-4.236

y = 4-x   = 4 – (-4.236)

= 8.236

y = 8-x^-1 =   .236)^-1

= 8.236

x=0.236

  y = 4-x   = 4 – (0.236) = 3.764

y = 8-x^-1 =   8-(0.236)^-1

= 3.764

thus the two lines cross at 2 points:

(-4.236, 8.236) & (0.236, 3.764)

c.   to solve

graphically the equation 4-x = 8-x^-1

we would graph both lines: y = 4-x   and   y

= 8-x^-1

the point on the graph where the lines cross is the

solution to the system of equations.

just graph the points on part b on a cartesian coordinate

system and extend the two lines.   the

solution is, as stated, the point where the two lines cross on the graph.

step-by-step explanation:

mark brainliest!