In a particular game, a spinner with four equally-sized sectors labeled 1, 3, 5, and 6 is spun twice. one turn is considered 2 spins of the spinner. if the sum of the spins is even, you move backward 6 spaces. otherwise, you move forward 2 spaces. what is the mathematical expectation for the number of spaces moved in one turn? 1 space forward 3 spaces backward 1 space backward 3 spaces forward

no, the equation would be invalid since they are both not equal.

step-by-step explanation:

here you got

4y-6+4y 2-9

first, you would simplify the equation on the form.

4y-6+4y 2-9

then, move all the terms that contains a y to the left and all the other terms to the right.

+4y-4y+-9-6

finally, you will simplify the left and the right side of the equation.

y=-3

the answer is 844

step-by-step explanation:

it is 844 because if you add 836.50 + 7.5 you will get 844

addition

step-by-step explanation:

60: 45 =12: 9 =4: 3 so the answer is 4: 3