Acircle has its center at (6,-3) and a radius of 5 units. what is the equation of the circle?

Step-by-step explanation:

The x value for the center is part of the x^2 part of the equation.

The y value for the center is part of the y^2 part of the equation.

The radius is squared.

(x - 6)^2 + (y + 3)^2 = 5^2  

Notice the sign change for the center. When you move horizontally the sign of the center changes sign in the circle's equation.

The graph is included to show you that.

step-by-step explanation:

in the absence of parentheses, i will have to make some assumptions:   i interpret your (3x+5/y^6)(4y^3/5)​ to mean:

3x + 5     4y^(3/5)       (3x + 5)(4)

* =

    y^6             1               y^(6-3/5)

if this is not what you expected, repost your question using parentheses to indicate whether you meant

4y^3

    or   4y^(3/5)

    5

in 4 days he will run   12/14

step-by-step explanation: