What is the standard form of the equation of the circle in the graph? (x + 3)^2 + (y + 3)^2 = 3 x^2 + y^2 = 9 x^2 + y^2 = 3 (x + 3)^2 + (y + 3)^2 =9

B

Step-by-step explanation:

The equation of a circle centred at the origin is

x² + y² = r² ← where r is the radius

here r = 3 ⇒ r² = 9, thus

x² + y² = 9 ← equation of circle

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3