Identify the values of a, b and c in the quadratic 7x^2-4x+5=6x-8

a = 7, b = -10 and c = 13.

Step-by-step explanation:

7x^2 - 4x + 5 = 6x - 8

Rearranging:

7x^2 - 4x - 6x + 5 + 8 = 0

7x^2 - 10x + 13 = 0

So a = 7, b = -10 and c = 13.

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

4 candies

step-by-step explanation:

7 x 28 = 196

200 - 196 = 4 candies remaining.