If the legs of a right triangle are 3 and 6, what is the length of the hypotenuse? round your answer to the nearest thousands if needed be

6.708

You can find this using the a^2 + b^2 = c^2 method, substituting the length of the legs for a and b, while solving for c.

6.708.

The Pythagorean theorem for finding the hypotenuse of a right triangle is a^2 + b^2 = c^2. So the equation goes as follows.

a^2 + b^2 = c^2

(3)^2 + (6)^2 = c^2

9 + 36 = c^2

45 = c^2

C = 6.708

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

boxplot e is the answer