Afast food restaurant sells burgers, chicken sandwiches, and entree salads. if a customer buys a burger, the probability they buy french fries is 0.80. fifty percent of customers who purchase a chicken sandwich also buy fries, but only 10% of those buying an entree salad buy fries. of all customers, 65% buy a burger, 20% a chicken sandwich, the rest buy an entree salad. what proportion of customers get a burger and fries?

52%

Step-by-step explanation:

We are told that, of all customers 65% buy a burger. This would imply that the proportion of customers who buy a burger is 0.65.

Moreover, if a customer buys a burger, the probability they buy french fries is 0.80. This implies that the proportion of customers who buy fries given that they bought a burger is 0.8.

Therefore, the proportion of customers who get a burger and fries is simply the product of the two probabilities;

= 0.65*0.8

= 0.52

Therefore, 52% of all customers get a burger and fries

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse