Find the value of this function 2x+3-x²-1*4

x_1= √-28/-2

x_2= 2 + √-28

Quadratic formula method: ↓

Step-by-step explanation:

Given) 2x + 3 - x² - 1 * 4

1) Communtative Property: 2x + 3 - x² - 1 * 4 = -x² - 1 * 4 + 2x + 3

2) Communtative Property: -x² - 1 * 4 + 2x + 3 = -x² + 2x - 1 * 4 + 3

3) Communtative Property: 2x - x² - 1 * 4 + 3

4) Solve: 2x - x² - 1 * 4 + 3

5) Solve: 2x - x² - 4 + 3

6) 2x - x² - 7

7) Communtative Property: -x² + 2x - 7

8a) Quadratic Formula: ax²+bx+c=0; x = ((-b)± √(b²-4ac))/2a

8b) Let -1=a, let 2=b, let -7=c

9a) Substitute -1 for a: x = ((-b)± √(b²-4(-1)c))/2(-1)

9b) Substitute 2 for b: x = ((-2)± √(2²-4(-1)c))/2(-1)

9c) Substitute -7 for c: x = ((-2)± √(2²-4(-1)(-7))/2(-1)

10a) Solve: (-2± √2²-4(-1)(-7))/-2 = (-2± √4 -4(-1)(-7))/-2

10b) Solve: (-2± √4 -4(-1)(-7))/2(-1) = (-2± √4+ -4(-1)(-7))/-2

11) Solve: (-2± √4 + -4(-1)(-7))/-2 = (-2± √4 + (4)(-7))/-2 = (-2± √4 + -28)/-2

12) Solve: (-2± √4 + √-28)/-2 = (-2±  2 + √-28)/-2

13a) Solve 1 way: (-2+  2 + √-28)/-2 = (0 + √-28)/-2 =

x_1= √-28/-2

13b) Solve 2 way: (-2-  2 + √-28)/-2 = (-4 + √-28)/-2 =

x_2= 2 + √-28

14) Or solve a different way... I'm pretty sure theres another, more accurate way to solve this. :(

I hope I helped. I wasn't very sure on how to do this though, sorry if I am wrong. :(

simplifying

5(x + -6) = 2(x + 3)

reorder the terms:

5(-6 + x) = 2(x + 3)

(-6 * 5 + x * 5) = 2(x + 3)

(-30 + 5x) = 2(x + 3)

reorder the terms:

-30 + 5x = 2(3 + x)

-30 + 5x = (3 * 2 + x * 2)

-30 + 5x = (6 + 2x)

solving

-30 + 5x = 6 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-30 + 5x + -2x = 6 + 2x + -2x

combine like terms: 5x + -2x = 3x

-30 + 3x = 6 + 2x + -2x

combine like terms: 2x + -2x = 0

-30 + 3x = 6 + 0

-30 + 3x = 6

add '30' to each side of the equation.

-30 + 30 + 3x = 6 + 30

combine like terms: -30 + 30 = 0

0 + 3x = 6 + 30

3x = 6 + 30

combine like terms: 6 + 30 = 36

3x = 36

divide each side by '3'.

x = 12

simplifying

x = 12

this should .