Aradio antenna is kept perpendicular to the ground by three wires of equal length. the wires touch the ground at three points on a circle whose center is at the base of the antenna. if the wires touch the ground at (9, −19), (−21, −19), and (14, 16), what are the coordinates of the base of the antenna? (−6, 1) ( 6,−1) (−4, 3) (4,−3)

s + (a + 178) = 2000

step-by-step explanation:

2000 - 178 = 1822

1822 / 2 = 911

911 + 178 = 1089

1089 + 911 = 2000

abha = 1089

shane = 911

false

step-by-step explanation:

rulers and compasses arent required in order to bisect an angle because when bisecting angles, you're making a "half circle" and considering in order to bisect an angle it wouldn't be straight, you wouldn't need either of the two

the rocket cannot penetrate the ground, in a contextual sense, therefore the roots of this equation should be the domain of this function. i'll let you find the roots of this quadratic equation (hint: use the quadratic formula:  

1- c

2-a

step-by-step explanation:

mark brainliest!